• Members 509 posts
    May 30, 2023, 9:26 p.m.

    Sure, kind of like a small version of a star throwing light in all directions. Or an explosion,

  • Members 13 posts
    May 31, 2023, 1:05 p.m.

    David, as You've already probably caught, the problem with Your model is because You treat the layers of liquid/gas like solid layers, which transfer outer forces only directionaly. This is not the case.
    In general, forces between particles may be attracting or reppelling, depending on the kind of molecules and their relative distances. It's a complex matter and I don't feel able to explain it in short anyway. But there are some consequences of them that create 3 states of matter: solid, liquid and gas.
    In solids, the final effect of intermolecular forces is that molecules maintain their positions. With some tolerance for thermal vibrations and some elasting shift caused by directional force. If You press a solid by directional force, it will cause some elastic deformation, mostly directional, but also sideways, both will be counteracted by by intermolecular forces, trying to stabilise molecular distances and positions. So any global directional force to the piece of solid (external or its own weight) will be transfered directionaly by the interaction between its molecules, because forces between them try to maintain their relative location (and globaly the shape of solid body).
    In liquid or gas it goes other way. Molecules can move and change their position constantly, due to weaker intermolecular forces. In liquid their distances are smaller, so there's constant strong interaction. It doesn't stop the movement, just holds average distances between them. In gas interaction is so weak, that in "perfect gas" model we assume that happens only at close encounters (so called "collisions").
    In both cases volume of liquid/gas doesn't maintain its shape. So any global force on the volume is transfered within in absolute random directions by intermolecular forces. It maintains the intensity, but not the direction.This leads to Pascal law. Pressure in liquid (both external or internal) can act creating forces in any direction. In case of contact with a solid object, the force created by liquid pressure (which is just constant "bombardment" of that surface by moving fluid molecules) is just perpendicular localy to that surface. So if this surface is on the top of the object, the force would be pointed down, if on its bottom - up. If on the side - to the side. etc.
    Why this force from fluid pressure is perpendicular to the solid surface? Simply: only perpendicular component of molecular hits do not cancel out in average. Side/parallel component of a hit from one molecule would be canceled out by another going from other side at the same angle & speed statistically.
    Regards,
    -J.

  • Members 509 posts
    May 31, 2023, 3:46 p.m.

    It's not actually true that I treat fluids as if they are solids, even if that is how it might seem. My initial model used only the kinetic motion of molecules to explain buoyancy and was roundly laughed at (not here). My new model is intended to avoid that laughter. Perhaps I have thrown out the baby with the bathwater.

    A while back I found an independent description of my kinetic model from someone else who had put numbers to it. To me this model seemed to explain everything I wanted about buoyancy in a way that Archimedes did not (to me). I showed this to a physicist/mathematician friend and he poured scorn on it. I could never quite work out what was wrong with it, but I assume there was something. I'll see if I can locate it again and reproduce it here. Perhaps you can tell me what's wrong with it and combined with what's wrong with my current model, I'll be able to home in on what really happens. Got to be optimistic!

    EDIT: Here we go. So what is wrong with this model?

    If a balloon rises there must be a net upward force on it that is greater than its weight. What produces this force?

    It must be the atmosphere. The atmosphere, made of gases moving at approximately 1000mph at 25 deg. Celsius striking the balloon produce a large surface force on the sphere. A balloon of diameter 30cm (~ one foot) has a surface area of 2826 cm^2. Each cm^2 experiences a force of 2.3 pounds (~10 newtons) for a total force on the balloon surface of about 6500 pounds. All from colliding gas molecules.

    What is missing in my calculations is the difference between the collisions on the bottom of the balloon compared to the top of the balloon. Because of gravity the atmosphere varies in density as the altitude changes. This results in a density gradient. Maximum density at sea level. Minimum at 60mi, considered the edge of space. The atmospheric pressure is directly proportional to density so, maximum pressure is at sea level decreasing to a minimum at 60mi. Even with an altitude difference of one foot there is a difference in the force upward on the balloon and the force down at the top of the balloon due to density of colliding gas molecules.

    If we change our balloon to a box with sides of 30cm (nearly a cubic foot), we can explore the force difference more easily.

    Since the density/pressure gradient is vertical the sides of the box experience the same horizontal forces due to colliding gas molecules resulting in a net force of zero horizontally. The box will not drift left or right.

    Vertically the atmospheric pressure changes about 0.035 mbar/1 ft. (near sea level) so the box bottom experiences a pressure of 1013.250 mbar pressure and the top would be 1013.215 mbar (- 0.035 mbar). Converting this pressure to force produces about 0.000078 pounds /cm^2 difference. For our box of 900cm^2 top and bottom areas results in a force difference of 0.070 pounds or 0.311 newtons or the weight of about 20 large paper clips.

    If the box and its contents weigh less than this difference it will rise.

    Source: www.quora.com/Why-are-less-dense-materials-rising-up-Do-they-have-some-kind-of-force-that-makes-them-rise (8th response from top)

  • May 31, 2023, 4:54 p.m.

    Good, it looks like this: (No references to Kurt Vonnegut intended.)

    Now I start with first model under some assumptions:

    • we have homogenous fluid or gaseous environment (our environment is not infinite, but boundaries are very far away and do not affect our model)
    • our environment is anisotropic - no preferred direction /edit: no one noticed terminology error here🙃/
    • we analyze only static conditions
    • we have no gravity or any other outside forces present

    I marked some virtual boundaries around really small volumes and few of your tiny forces on those boundaries on next drawing - note that all forces are numerically equal (boundary lengths on picture are same) and perpendicular to boundaries. I hope these claims do no need explanations, they are based on our assumptions alone - but if required, I can explain more.
    Also I hope that despite my image being 2D and I'm talking about boundaries length, we can safely assume that in reality situation is 3D and boundaries have same surface area - this does not change overall picture.

    model-1.png

    Is such image/situation agreeable and understandable?

    model-1.png

    PNG, 211.6 KB, uploaded by ArvoJ on May 31, 2023.

  • Members 509 posts
    May 31, 2023, 7:12 p.m.

    Looks good...

  • May 31, 2023, 7:33 p.m.

    OK, now we take two more steps (maybe they are side steps, but I think they may help later), continuing without gravity.

    1. We can safely assume that virtual boundaries are real boundaries (surfaces), infinitely thin, weightless, rigid and elastic (elastic here means there will not be absorbtion of collision energy) - entire picture will look exactly the same.
    2. We remove water from one "cell", resulting in next situation:

    model-2.png

    Now we have similar looking forces, but their meaning is somewhat changed.

    Green arrows are your tiny forces from previous model - water molecules colliding with something.
    Red arrows are reaction forces to water molecules impacts. (They are of electrostatic nature as well - as are almost all forces between molecules.)

    As we have no gravitation, overall picture does not change - cell walls elastic reaction replaces previous water molecules action.
    We can leave cell empty or put anything inside evacuated cell, this does not affect surrounding fluid/gase behavior at all.

    model-2.png

    PNG, 221.1 KB, uploaded by ArvoJ on May 31, 2023.

  • Members 13 posts
    June 1, 2023, 7:10 a.m.

    David, once again the same old mistake: remove density greadient from Your model. It has nothing to buoyancy itself (as it exist both in gas and in liquid, right?), just is one of the causes (together with temperature) to buoyancy change with altitude of flight within atmosphere.
    This is only pressure gradient due to fluid column height differenc around the floating object that causes buoyancy, nothing more.
    Regards,
    -J.

  • Members 509 posts
    June 1, 2023, 7:28 a.m.

    So which bits of that description are physically wrong? The author, Greg, is certainly correct that there is an atmospheric pressure gradient otherwise no one would need to carry oxygen to climb Everest.

    If there is physically an atmospheric gradient, how can we ignore it? I would have thought that anyone looking at Greg's description would think it must be true, how could it be otherwise? It's sounds perfectly logical. An atmospheric gradient exists therefore there must be a pressure difference even over the short distance of the height of the balloon.

    I can't help but feel that if this model is incorrect, it needs to be explained why it is incorrect before we move on. I assume there are misunderstandings about the exact physical conditions present or there are omissions. But we need to falsify it in detail, otherwise, all we are left with is an unexplained pre-knowledge that your last sentence is correct. I'm not wedded to the Greg model. Something about it "feels" as if it can't be right. But I want to understand in detail (rather than by assertion) why it doesn't work. I've been unable to explain it away myself, but no one I've asked has been able or willing to do so either, so far. Instead, they dismiss it as nonsense without actually refuting it.

    I'm sure it must be wrong, but why?

    p.s.

    This thread does show how subtle physics it and how easy it is to come up with incorrect or misunderstood explanations. It took 10,000 years of civilisation to arrive at the current understanding, it's hardly a surprise that trying to re-invent the ideas from scratch can run into difficulties.

  • Members 509 posts
    June 1, 2023, 7:54 a.m.

    If the green arrows represent a force acting towards the open space and there is nothing there to apply an opposite force, will that cause the cells surrounding that space to move into it? Or are those molecules locked in place so the green force just distorts the "wall" facing the open void?

    p.s.

    I'm leaving today (Thurs) on an overnight trip and probably won't be looking at this thread again until Sat morning. Please carry on if you are happy to do so, it's most appreciated.

  • June 1, 2023, 10:10 a.m.

    From p1 - we replaced virtual boundaries with real solid walls, wall molecules are locked and just react to water molecules impacts - red arrows. Nothing can flow through these walls.

    My main point was to show that at least in static conditions without gravity we can replace any volume of environment (water/gas) with some hard object and absolutely nothing will change in surrounding water or gas environment - all forces remain the same.

    I'll continue after you return :)

  • Members 13 posts
    June 1, 2023, 12:39 p.m.

    David, You now writing about pressure gradient (which is correct both in liquid and gas under gravity), but before (and this is what I was reffering to) You have written about density gradient which is severe only in gas (air/atmospfere) and has no meaning for creating buoyancy itself. Just for its changes with altitude (and temperature). In fact those changes exist also in liquids, but are minimal compared to gas and more dependant upon temperature than pressure.
    So don't put density change into understanding buoyancy as it is. It of course and only explains the change of buoyancy with altitude. But not the very existence of buoyancy.
    Regards
    -J.

  • Members 599 posts
    June 3, 2023, 6:45 p.m.

    Blow-Up a1966 mystery thriller film directed by Michelangelo Antonioni, has this very thing throughout it. Watch it if you haven't already- true classic!

  • Members 138 posts
    June 3, 2023, 9:44 p.m.

    Been staring at this thread title for a few days, muddling through the "proper exposure" thread l'd say I can't explain every single photograph I've ever taken... 😆

  • Members 509 posts
    June 5, 2023, 6:37 a.m.

    I may be writing about pressure gradient but if so, only by accident. It's quite clear the "Greg" piece is about a density gradient. The whole argument rests on the idea that there is a density gradient present and the consequences of that is that there are more molecules at the bottom of the balloon than at the top and the consequence of that is even if each molecule hits the balloon with exactly the same force irrespective of its position, the the overall effect is more forces applied at the bottom than the top.

    My intuition today is that this can't be right. And many people over the years have queued up to say it isn't right. But I'm not sure why it isn't right, it sounds right, but none of them so far has gone beyond "that is not right". Nobody seems willing to able to explain exactly why it isn't right in terms of the behaviour of individual molecules. There must be an obvious error or an unspoken error or something is omitted but if that is the case, why can't people just explain it very simply: "Those 4 molecules at the bottom that provide the lift in this model don't exist, or their forces operate at right angles to the direction the model suggests", or something of this nature. My take away from this situation is that there are a lot of people who struggle to accurately describe physical situations, even those who believe they have a good understanding. Probably because physics is subtle.

    No doubt, when someone finally hits on the correct microscopic description, it will be face palm time and I'll be saying "Ah, of course, that's how it works. How obvious and how silly of me to think otherwise". I'm looking forward to that moment of enlightenment but I've been waiting 20 years so far, patience is a virtue...

  • June 5, 2023, 7:07 a.m.

    Exactly!
    I have theory - if one cannot explain what one knows well, then one doesn't know it so well, after all...

    If you have understood my drawings and explanations so far, let me know; then I'll continue later today with more complex situation.
    If not, then just ask over.

  • Members 509 posts
    June 6, 2023, 9:44 a.m.

    I hurt my back a couple of days ago which is limiting my ability to sit at the computer for long periods at the moment. But please carry on...

  • June 6, 2023, 5:09 p.m.

    I hope it is nothing serious!


    But well, let's continue.
    To recall most important claims and conclusions so far, for fluid or gaseous environment in static conditions:

    • our 'tiny forces' are caused by chaotic, non-directional movement and can thereby drawn as , not ↗ or ↙ or something else with clear direction
    • without external forces (gravity) we can replace any part of our environment with some solid object, this does not change any forces in surrounding environment

    Now we will introduce gravity, first without any additional objects or real walls in our environment (boundaries between 'cells' are again purely imaginary).

    model-3.png

    As you can see, there appeared additional force to our tiny water droplet - bluish arrow on picture. Similar forces, caused by gravity, apply of course to all other 'cells' too.
    But we have condition that our model has to be static - this means that we must have some other force(s), balancing gravitational one. As there are no more 'big' forces, then apparently our 'tiny forces' need to be reconfigure itself in some way - in lower part of our droplet they need to be stronger (water molecules need to kick harder). As our forces are in form and symmetrical (otherwise water would start to flow into other directions, which is excluded by static nature of our model), then we can first conclude that they are equal at the same level (at same gravitational potential) and then that applying gravity creates 'tiny forces' gradient in entire environment, aligned in directon of gravity.
    As you can see on image, 'tiny' forces at lower level are drawn as longer arrows. Of course if our cell is tiny, then real forces differ much less - but they are certainly different.

    Although some words are explicitly forbidden here 🙃, I will anyway note that those non-directional forces are called pressure. Previous claim can also be reworded as "applying gravity to fluidous/gaseous environment creates pressure gradient".

    model-3.png

    PNG, 225.6 KB, uploaded by ArvoJ on June 6, 2023.

  • Members 509 posts
    June 8, 2023, 12:33 p.m.

    Just got back from seeing the physio at my GP's surgery. She has given me an exercise to treat my "trigger finger" problem (fingers lock in position and won't move) - likely caused by typing too much stuff about buoyancy 🙂, she's diagnosed my shoulder/arm problem and will send me an exercise programme to deal with that, but the back will have to wait for another appointment. Hopefully it will get a bit better on its own.

    My description of your scenario above:

    In the absence of gravity, we have a bunch of particles all vibrating randomly. Each particle moves randomly back and forth about a point. This movement causes there to be lots of random collisions with neighbouring forces. On average, these cancel out and thus we have a static situation.

    With gravity added, all the molecules also have the force of gravity pushing (pulling) them downwards towards their neighbours below (who push back equally and oppositely). The whole group of particles should fall as a block. No idea how the block remains in a static position.

  • June 8, 2023, 6:20 p.m.

    I should have guessed that 🙃
    You inverted my assumption - remember, we have static situation and we need to find out, what happens then.

    But well, let's confine our water somehow - like I said many postings ago, to hold water in place we have to put some walls somewhere. Like on next image:

    model-3-1.png

    Now we have perfectly bottled water, gravity is vertical, our tiny droplet is also located there (my previous model is just magnification of it).
    I did not draw forces at water-bottle surface, but they are reaction forces to water molecules, similar situation we have talked before.
    I won't explain what happens at the top surface of water - this is very different topic.

    By orange lines I have marked levels, where tiny forces (pressure) have to be equal.
    Can you explain, why? In few words, to not hurt your finger :)

    model-3-1.png

    PNG, 491.7 KB, uploaded by ArvoJ on June 8, 2023.

  • Members 509 posts
    June 12, 2023, 9:48 a.m.

    Assuming the blob of water is held in place by the walls of the bottle, and assuming your orange line goes through the centre, I guess forces half to balance to prevent the top half of the blob pushing the bottom half out of the way (or the reverse).

    But I doubt somehow that is what you meant....Please enlighten me 🙂

  • June 14, 2023, 8:42 p.m.

    For given tiny cell it is correct. A bit more generally - molecules below some water volume need to counteract to weight of 'upper' molecules; they would gladly move away - but there is nowhere to go, molecules in the neighbourhood have similar 'pressure' from upper ones and then we have walls, which don't go away. 'Lower' molecules thereby just need to kick harder (= exert bigger force) to keep situation stable.

    Then we claim that forces on same level are equal.
    Remember that the only external force (gravity) is vertical, there is no horizontal component of it - this implies that forces cancel out in horizontal direction or in other words, they are just equal. Or in prohibited :) words - pressure at the same level is equal.
    (Wikipedia calls related principle as 'Communicating vessels'.)

    This holds even in strange geometric forms, like our bottle above - pressure at a level, marked by orange line, is equal in all three areas.

    Can we use the word pressure for our tiny forces from now or should I continue to avoid that?
    I mean do you start seeing pressure as a result of omnidirectional (molecular) forces or not yet?
    Few posts ago you attempted to assign direction to pressure, this is not possible in our static fluid or gaseous environment - I hope you have changed your mind :)

    (I'm really not a teacher kind of person.)

  • Members 509 posts
    June 19, 2023, 2:46 p.m.

    Sorry about the slowness in replying. Minor medical problems have kept me away from the keyboard plus I've been ferrying my daughter around the country to university open days. Got more to do as well.